Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.3 - Logarithmic Functions - 4.3 Exercises - Page 353: 77

Answer

Domain: $(0,2)$

Work Step by Step

For a logarithmic function to be defined, its argument must be POSITIVE, So, g is defined for $ x>0\qquad$and$\qquad 2-x>0$ (both terms must be defined) $\left[\begin{array}{lll} x>0 & & 2-x>0\\ & & 2>x \end{array}\right]$ So, x is greater than 0 and less than 2, Domain: $(0,2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.