## Precalculus: Mathematics for Calculus, 7th Edition

a.) $\ln 0.5 = x+1$ b.) $\ln t = 0.5x$
$Express$ $the$ $equation$ $in$ $logarithmic$ $form:$ a.) $e^{x+1} = 0.5$ b.) $e^{0.5x} = t$ Exponential form to natural log form: $e^b = a \rightarrow \ln a = b$ [Note: e means euler's number, NOT a variable] a.) $e^{x+1} = 0.5$ Plug in x+1 for b and 0.5 for a $e^{x+1} = 0.5 \rightarrow \ln 0.5 = x+1$ b.) $e^{0.5x} = t$ Plug in 0.5x for b and t for a $e^{0.5x} = t \rightarrow \ln t = 0.5x$