Answer
a.) $\log_6 36 = 2$
b.) $\log \frac{1}{10} = -1$
Work Step by Step
$Express$ $the$ $equation$ $in$ $logarithmic$ $form:$
a.) $6^2 = 36$
b.) $10^{-1} = \frac{1}{10}$
Exponential form to logarithmic form: $b^c = a \rightarrow \log_b a = c$
a.) $6^2 = 36$
Plug in 6 for b, 2 for c, and 36 for a
$6^2 = 36 \rightarrow \log_6 36 = 2$
b.) $10^{-1} = \frac{1}{10}$
Plug in 10 for b, -1 for c, and $\frac{1}{10}$ for a
$10^{-1} = \frac{1}{10} \rightarrow \log_{10} \frac{1}{10} = -1 \rightarrow \log \frac{1}{10} = -1$