## Precalculus: Mathematics for Calculus, 7th Edition

a.) $e^2 = (x+1)$ b.) $e^4 = (x-1)$
$Express$ $the$ $equation$ $in$ $exponential$ $form:$ a.) $\ln (x+1) = 2$ b.) $\ln (x-1) = 4$ Natural Log form to exponential form: $\ln a = b \rightarrow e^b = a$ [Note: e means euler's number, NOT a variable] a.) $\ln (x+1) = 2$ Plug in (x+1) for a and 2 for b $\ln (x+1) = 2 \rightarrow e^2 = (x+1)$ b.) $\ln (x-1) = 4$ Plug in (x-1) for a and 4 for b $\ln (x-1) = 4 \rightarrow e^4 = (x-1)$