Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.1 - Exponential Functions - 4.1 Exercises: 7

Answer

$f(\frac{1}{2}) = 2 \\f(\sqrt5) \approx 22.195 \\f(-2) \approx 0.063 \\f(0.3) \approx 1.516$

Work Step by Step

Substitute each of the given values of $x$ then solve for $f(x)$. Use a calculator to have: $\\f(\frac{1}{2})=4^{\frac{1}{2}} = 2 \\f(\sqrt{5}) = 4^{\sqrt5} \approx 22.195 \\f(-2)=4^{-2} \approx 0.063 \\f(0.3)= 4^{0.3} \approx 1.516$
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