## Precalculus: Mathematics for Calculus, 7th Edition

$f(\frac{1}{2}) = 2 \\f(\sqrt5) \approx 22.195 \\f(-2) \approx 0.063 \\f(0.3) \approx 1.516$
Substitute each of the given values of $x$ then solve for $f(x)$. Use a calculator to have: $\\f(\frac{1}{2})=4^{\frac{1}{2}} = 2 \\f(\sqrt{5}) = 4^{\sqrt5} \approx 22.195 \\f(-2)=4^{-2} \approx 0.063 \\f(0.3)= 4^{0.3} \approx 1.516$