Answer
Graph II
Work Step by Step
With close speculation of the equation, we see that $y=5^{(x+1)}$ is an exponential function with no constant term. Thus the graph is rather a translation of 1 unit to the left of $5^x$ and the graph must have a point at (1-1,5) instead of the latter equation's (1,5). The graph with (0,5) present is Graph II.