Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.1 - Exponential Functions - 4.1 Exercises - Page 336: 10

Answer

$log_{6}$ (9*24) = 3

Work Step by Step

1.The Law that will be used here is $log_{a}$ (AB) = $log_{a}$ (A) + $log_{a}$ (B). 2. Combine 9 and 24 to get $log_{6}$ (9*24) = $log_{6}$ (216). 3. Evaluating $log_{6}$ (216) gives you the answer of 3. 4. If evaluating the log way is harder, convert $log_{6}$ (216) to $6^{x}$ = 216, Solving for X, the exponent, will also give you 3.
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