Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.7 - Polynomial and Rational Inequalities - 3.7 Exercises - Page 316: 33

Answer

$[-2.0)\cup(1,3]$

Work Step by Step

1. Move all items to one side: $f(x)=\frac{6}{x-1}-\frac{6}{x}-1\geq0$ $\frac{6x-6x+6-x^2+x}{x(x-1)}=\frac{-(x-3)(x+2)}{x(x-1)}\geq0$ 2. Cut points $-2,0,1,3$, build up a sign table as shown. 3. Solutions $[-2.0)\cup(1,3]$
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