Answer
$Q(x)=(x-5)(x+5)(x-5i)(x+5i)$
Zeros: $5$ , $-5$ , $5i$ , $-5i$,
each with multiplicity 1.
Work Step by Step
$Q(x)=(x^{2})^{2}-25^{2}= \qquad $...difference of squares...
$=(x^{2}-25)(x^{2}+25)$
$x^{2}-25= x^{2}-5^{2}\quad $...difference of squares...$=(x-5)(x+5)$
$x^{2}+25=x^{2}-(-1)\cdot 5^{2}=x^{2}-(5i)^{2} \qquad $...difference of squares...$=(x-5i)(x+5i)$
$Q(x)=(x-5)(x+5)(x-5i)(x+5i)$
Zeros: $5$ , $-5$ , $5i$ , $-5i$,
each with multiplicity 1.