Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.4 - Real Zeros of Polynomials - 3.4 Exercises - Page 285: 87

Answer

See prove below.

Work Step by Step

1. List all possible rational zeros as $\pm1,\pm2$ 2. Use remainder theorem or synthetic division to test the above values $P(1)=1-1-2=-2, P(-1)=-1+1-2=-2, P(2)=8-2-2=4,P(-2)=-8+2-2=-8$ 3. As the values in the list are not zeros, we conclude that there are no rational zeros.
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