Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.2 - Polynomial Functions and Their Graphs - 3.2 Exercises - Page 266: 40

Answer

(2, 0) (-3/2,0) See graph below.

Work Step by Step

$P(x) = 0.125 (2x^4 + 3x^3 - 16x -24)^2$ $P(x) = \frac {1}{8} (x^3 (2x +3) - 8 (2x + 3))^2$ $P(x) = \frac {1}{8} ((x^3 - 8) (2x + 3))^2$ $P(x) = \frac {1}{8} (x-2)^2(x^2 + 2x + 4)^2 (2x+3)^2$ Thus the zeros are (2, 0) (-3/2,0)
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