Answer
(-1, 0) and (1,0)
See Graph Below
Work Step by Step
$P(x) = x^3 + x^2 - x - 1$
$P(x) = x^2 (x + 1) - 1 (x + 1)$
$P(x) = (x^2 - 1) (x+1)$
$P(x) = (x-1) (x+1) (x+1)$
Thus the zeros are (-1, 0) and (1,0)
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