Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Section 3.1 - Quadratic Functions and Models - 3.1 Exercises - Page 253: 59

Answer

Length - $600ft$ Width - $1200ft$

Work Step by Step

We have the following values : Length - $x$ $ft$ Width - $(2400-2x)$ $ft$ Let $A$ be the area of the rectangle. $A=x(2400-2x)=-2x^2+2400x$ The value of $x$ for the largest possible value of the area is calculated by the formula : $x=-\frac{b}{2a}$ In our case we have : $a=-2$ $b=2400$ $x=-\frac{2400}{-4}=600$ So, we have : Length - $600ft$ Width - $2400-2\times600=1200ft$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.