Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Review - Exercises - Page 321: 57

Answer

$1, -i, i$

Work Step by Step

This question asks for ALL zeros of the function Given $P(x) = x^3 - x^2 + x - 1$ $P(x) = x^2 (x-1) + 1 (x-1)$ $P(x) = (x^2 + 1)(x-1)$ Set each polynomial equal to one $x-1 = 0$ $x = 1$ $x^2 + 1 = 0$ $x^2 = -1$ $x = +/- i$ Thus the solutions are $1, -i, i$
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