Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Review - Exercises - Page 320: 7

Answer

$68$ft

Work Step by Step

As we are given that $h(t)=-16t^2+48t+32$ Here, $a=-16,b=48,c=32$ and $a =-16 \lt 0$ and this shows a maximum value at the point $h=\dfrac{-b}{2a}=-\dfrac{(48)}{2(-16)}=1.5$ Consider: $k=h(1.5)=-16(1.5)^2+48(1.5)+32$ Thus, the maximum height or value of the stone reaches at: $k= 68$ft
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