Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 3 - Review - Exercises - Page 320: 6

Answer

$-22$

Work Step by Step

As we are given that $f(x)=3x^2-18x+5$ Here, $a=3,b=-18,c=5$ and $a =3 \gt 1$ and this shows a minimum value at the point $h=\dfrac{-b}{2a}=-\dfrac{(-18)}{2(3)}=3$ Now, $f(3)=3(3)^2-18(3)+5$ Thus, the minimum value of the function is: $f(3)= -22$
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