Answer
With $h(x)=3+\sqrt{x},\quad g(x)=x^{2},\ \quad$and $f(x)=\displaystyle \frac{2}{x}$,
$G(x)=f(g(h(x)))=(f\circ g\circ h)(x)$
Work Step by Step
If we were to calculate by hand,
we would find the square root of the number and add 3 $\qquad$...$ h(x)=3+\sqrt{x}$,
then square ( the number )$\qquad$ .... $g(x)=x^{2}$
and then divide 2 with the number $\qquad$ .... $f(x)=\displaystyle \frac{2}{x}$
In this way, $G(x)=f(g(h(x)))=f\circ g\circ h(x)$
(Note: this not the only way to do it)