Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.7 - Combining Functions - 2.7 Exercises - Page 217: 72

Answer

With $h(x)=3+\sqrt{x},\quad g(x)=x^{2},\ \quad$and $f(x)=\displaystyle \frac{2}{x}$, $G(x)=f(g(h(x)))=(f\circ g\circ h)(x)$

Work Step by Step

If we were to calculate by hand, we would find the square root of the number and add 3 $\qquad$...$ h(x)=3+\sqrt{x}$, then square ( the number )$\qquad$ .... $g(x)=x^{2}$ and then divide 2 with the number $\qquad$ .... $f(x)=\displaystyle \frac{2}{x}$ In this way, $G(x)=f(g(h(x)))=f\circ g\circ h(x)$ (Note: this not the only way to do it)
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