Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.5 - Linear Functions and Models - 2.5 Exercises - Page 197: 45

Answer

(a) Jari (b) Jade: $60 \space mi/h$ | Jari: $70 \space mi/h$ (c) $f(t) = t + 10$ and $g(t) = \frac 7 6 t $

Work Step by Step

(a) - From t = 0 to t = 6, Jade traveled 6 miles, and Jari traveled 7 miles. Therefore, $Jari$ is moving faster. (b) Jade: $speed = a = \frac{16 - 10}{6 - 0} = \frac 6 6 = \frac{1 \space mi}{min} \times \frac{60 \space min}{1 \space h} = 60 \space mi/h$ Jari : $speed = a = \frac{7 - 0}{6 - 0} = \frac {7 \space mi} {6 \space min} \times \frac{60 \space min}{1 \space h} = 70 \space mi/h$ (c) ** Notice: $a$ must be in $\frac{mi}{min}$ Jade: f(t) = at + b At 7:00 A.M. Jade had already traveled 10 miles. b = 10 $$f(t) = (1)t + 10 = t + 10$$ Jari: g(t) = at + b At 7:00 A.M. Jari started moving. b = 0 $$g(t) = \frac 7 6 t $$
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