Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises - Page 188: 29

Answer

$-0.25$ ft/day

Work Step by Step

From the given graph, apply the formula such as: $\dfrac{W(x_2)-W(x_1)}{x_2-x_1}$ Plug the given data in the above formula. we have $\dfrac{W(x_2)-W(x_1)}{x_2-x_1}=\dfrac{W(200)-W(100)}{200-100}$ This gives: $\dfrac{W(200)-W(100)}{200-100}=\dfrac{50-75}{100}$ or, $\dfrac{W(200)-W(100)}{200-100}=-0.25$ ft/day
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