Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.4 - Average Rate of Change of a Function - 2.4 Exercises - Page 188: 20

Answer

a) $-12h-3h^2$ b) $-12-3h$

Work Step by Step

a) $f(2)=1-3\times2^2=1-12=-11$ $f(2+h)=1-3\times(2+h)^2=1-3(4+4h+h^2)=-11-12h-3h^2$ $f(2+h)-f(2)=-11-12h-3h^2-(-11)=-12h-3h^2$ b) $\frac{-12h-3h^2}{2+h-2}=\frac{-12h-3h^2}{h}=-12-3h$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.