Answer
a) $-12h-3h^2$
b) $-12-3h$
Work Step by Step
a) $f(2)=1-3\times2^2=1-12=-11$
$f(2+h)=1-3\times(2+h)^2=1-3(4+4h+h^2)=-11-12h-3h^2$
$f(2+h)-f(2)=-11-12h-3h^2-(-11)=-12h-3h^2$
b) $\frac{-12h-3h^2}{2+h-2}=\frac{-12h-3h^2}{h}=-12-3h$
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