Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.2 - Graphs of Functions - 2.2 Exercises - Page 168: 59

Answer

The equation DOES NOT define $y$ as a function of $x$.

Work Step by Step

Solve for $y$ in terms of $x$ to have: $\pm \sqrt{x} = y \\y=\pm \sqrt{x}$ The last equation is a rule that gives two values of $y$ for each valid value of $x$ (except x=0). Thus, it does not define $y$ as a function of $x$
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