Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.1 - Functions - Exercises: 43

Answer

$f(a) =5 - 2a $ $f(a+h)= 5 - 2a - 2h$ $\frac{f(a+h) - f(a)}{h} =-2 $

Work Step by Step

$$f(x) = 5 - 2x$$ $f(a) = 5 - 2a $ $f(a+h)= 5 - 2(a +h) = 5 - 2a - 2h $ $\frac{f(a+h) - f(a)}{h} = \frac{(5 - 2a -2h) -(5-2a)}{h} $... simplify numerator $=\frac {5-2a-2h-5+2a}{h}=\frac {-2h}{h}= -2 $
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