Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.1 - Functions - Exercises: 37

Answer

$$f(x^2) =x^2 +4 $$ $$(f(x))^2 =x^2 + 8x +16 $$

Work Step by Step

For x = $x^2$ $f(x^2) = x^2 +4 $ _______________ $f(x) = x + 4$ therefore $(f(x))^2 = (x+4)^2$ ... square the polynomial $=x^2 + 8x +16$
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