Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.1 - Functions - Exercises - Page 157: 35

Answer

$f(x+2) =x^2 + 4x + 5$; $f(x) + f(2) = x^2 + 6$

Work Step by Step

For x = x+2 $f(x+2) = (x+2)^2 + 1$ ... square (x+2) $= x^2 +4x +4 +1$ ... add $= x^2 +4x +5$ _____________ For x = 2 $f(2) = (2)^2+1$ ... square 2 $ = 4 + 1$ ... add $=5$ therefore $f(x) + f(2) = x^2 + 1 + 5$ ... add $= x^2 + 6$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.