Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.1 - Functions - Exercises: 35

Answer

$f(x+2) =x^2 + 4x + 5$; $f(x) + f(2) = x^2 + 6$

Work Step by Step

For x = x+2 $f(x+2) = (x+2)^2 + 1$ ... square (x+2) $= x^2 +4x +4 +1$ ... add $= x^2 +4x +5$ _____________ For x = 2 $f(2) = (2)^2+1$ ... square 2 $ = 4 + 1$ ... add $=5$ therefore $f(x) + f(2) = x^2 + 1 + 5$ ... add $= x^2 + 6$
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