## Precalculus: Mathematics for Calculus, 7th Edition

$f(-3)=5$ $f(0)=5$ $f(2)=5$ $f(3)=3$ $f(5)=7$
For $f(-3), f(0)$ and $f(2)$, $-3,0,2\leq2$ hence $$f(-3)=5$$ $$f(0)=5$$ $$f(2)=5$$For $f(3)$ where $x=3\gt;2$ hence $f(3)=2(3)-3=6-3=3$ For $f(5)$ where $x=5\gt;2$ hence $f(5)=2(5)-3=10-3=7$