Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Section 2.1 - Functions - Exercises: 19

Answer

${f(-3)=3}$ ${f(3)=3}$ ${f(0)=-6}$ ${f(\frac{1}{2})=-\frac{23}{4}}$

Work Step by Step

$${f(-3)=(-3)^2-6}$$ $${f(-3)=9-6}$$ $${f(-3)=3}$$ $${f(3)=(3)^2-6}$$ $${f(3)=9-6}$$ $${f(3)=3}$$ $${f(0)=(0)^2-6}$$ $${f(0)=0-6}$$ $${f(0)=-6}$$ $${f(\frac{1}{2})=(\frac{1}{2})^2-6}$$ $${f(\frac{1}{2})=\frac{1}{4}-6}$$ $${f(\frac{1}{2})=\frac{1}{4}-6\times\frac{4}{4}}$$ $${f(\frac{1}{2})=\frac{1}{4}-\frac{24}{4}}$$ $${f(\frac{1}{2})=-\frac{23}{4}}$$
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