Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Test - Page 236: 14

Answer

$f(x)=\frac{5x-3}{2x-1}$

Work Step by Step

Step 1: Switch $f(x)$ or $y$ and $x$ in the original function. $x=\frac{y-3}{2y+5}$ Multiply both sides by the denominator to cancel out the denominator. $2xy-5x = y-3$ Add $5x$, then subtract $y$. $2xy-y=5x-3$ Factor out y. $y(2x-1)=5x-3$ Divide by $2x-1$. $y=\frac{5x-3}{2x-1}$ or $f(x)=\frac{5x-3}{2x-1}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.