Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Test - Page 235: 6

Answer

Net change: $h^2+2h$ Avg. rate of change: $h+2$

Work Step by Step

Net change: $f(b)-f(a)=$ $f(2+h)-f(2)=$ $(2+h)^2-2(2+h)-(2^2-2(2))=$ $4+4h+h^2-(4+2h)-(4-4)=$ $4+4h+h^2-4-2h=$ $h^2+2h$ Avg. rate of change: $\frac{f(b)-f(a)}{b-a}$ $f(b)-f(a)$ was already found above, so: $\frac{h^2+2h}{2+h-2}=$ $\frac{h(h+2)}{h}=$ $h+2$
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