Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Modeling with Functions - Problems - Page 241: 12

Answer

$L(d)=\frac{5}{7}d$

Work Step by Step

There is an equal proportion of the heights and their bases: $\frac{L+d}{L}=\frac{12}{5}$, so one just needs to solve for L to find the equation $\frac{L}{L}+\frac{d}{L}=\frac{12}{5}$ $1+\frac{d}{L}=\frac{12}{5}$ $1-1+\frac{d}{L}=\frac{12}{5}-1$ $\frac{d}{L}=\frac{7}{5}$ $\frac{d}{L}\cdot L \cdot\frac{5}{7} =\frac{7}{5}\cdot \frac{5}{7}\cdot L$ $d \cdot\frac{5}{7} =L$ $L(d)=\frac{5}{7} d$
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