Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 232: 22

Answer

$(-\infty,-4)\cup(-4,\infty)$

Work Step by Step

The numerator is defined for all real numbers x, as the third root exists for all reals. The denominator is defined for all x. We need to exclude the ones that yield 0 $\sqrt[3]{2x}=-2\quad/ (...)^{3}$ $2x=-8$ $x=-4$ Domain of f: $(-\infty,-4)\cup(-4,\infty)$
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