Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 2 - Review - Exercises - Page 231: 1

Answer

$f(x)=x^{2}-5$

Work Step by Step

"Square, then subtract $5$" Let $x$ be the independent variable for $f$ First, square $x$: $x^{2}$ To that, subtract $5$ $x^{2}-5$ The function described is $f(x)=x^{2}-5$
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