Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 13 - Section 13.2 - Finding Limits Algebraically - 13.2 Exercises - Page 913: 42

Answer

$0$

Work Step by Step

With $x\to 0^+$, we have $x\gt0$ and $|x|=x$, thus $$\lim_{x\to 0^+}(\frac{1}{x}-\frac{1}{|x|} )=\lim_{x\to 0^+}(\frac{1}{x}-\frac{1}{x})=\lim_{x\to 0^+}(0)=0$$
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