## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 13 - Section 13.2 - Finding Limits Algebraically - 13.2 Exercises: 20

#### Answer

$\frac{3}{5}$

#### Work Step by Step

$\frac{x^{2}+5x+4}{x^{2}+3x-4}$ Simplify $\frac{(x+4)(x+1)}{(x+4)(x-1)}$ Cancel out like terms $\frac{x+1}{x-1}$ Substitute x for -4 $\frac{(-4)+1}{(-4)-1}=\frac{(-3)}{(-5)}= \frac{3}{5}$

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