## Precalculus: Mathematics for Calculus, 7th Edition

When solving limits, the first step to attempt is direct substitution, meaning plugging in the value of what the limit is approaching into the equation. In this case, plugging in $2$ to the function $$\frac{2-x}{x^2+1}$$ will give $$\frac{2-2}{2^2+1}$$ which further simplifies to $\frac{0}{5}$ or $0$