Answer
$(0,0)$ is not on the graph of the equation.
$(1,0)$ is on the graph of the equation.
$(-1,-1)$ is on the graph of the equation.
Work Step by Step
$x-2y-1=0$ $;$ $(0,0)$ $,$ $(1,0)$ $,$ $(-1,-1)$
Substitute each point into the equation:
$(0,0)$
$x-2y-1=0$
$0-2(0)-1=0$
$0-0-1=0$
$-1\ne0$ False
Substituting the point $(0,0)$ did not make the left side of the equation equal to the right side. This point is not on the graph of the equation.
$(1,0)$
$x-2y-1=0$
$1-2(0)-1=0$
$1-0-1=0$
$0=0$ True
Substituting the point $(1,0)$ into the equation makes it true. This point is on the graph of the equation.
$(-1,-1)$
$x-2y-1=0$
$-1-2(-1)-1=0$
$-1+2-1=0$
$0=0$ True
Substituting the point $(1,0)$ into the equation makes it true. This point is on the graph of the equation.