Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 103: 48

Answer

$$B(10,13)$$

Work Step by Step

We have midpoint $M(6,8)$ of $AB$. $A(2,3)$ $B(x,y)$ $\frac{2+x}{2}=6$ $2+x=12$ $x=10$ $\frac{3+y}{2}=8$ $3+y=16$ $y=13$ We have $B(10,13)$
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