Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 102: 28

Answer

(a) Refer to the image below for the plot. (b) Distance between the two points: $\sqrt{41} \approx 6.40$ units (c) Midpoint of the segment joining the two points: $(-3,5, -1)$

Work Step by Step

(a) Refer to the attached image in the answer part for the plot. (b) Solve for the distance between the two points using the distance formula $d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$ to have: $d=\sqrt{[-1-(-6)]^2+[1-(-3)]^2} \\d=\sqrt{5^2+4^2} \\d=\sqrt{25+16} \\d=\sqrt{41} \\d\approx 6.40$ (c) Find the mmidpoint of the segment that joins them by using the midpoint formula: $\text{midpoint}=\left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right)$ Midpoint = $\left(\frac{-1+(-6)}{2}, \frac{1+(-3)}{2}\right)=(-3.5, -1)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.