Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 101: 6

Answer

Center $(1, 2)$ Radius = $3$ units

Work Step by Step

RECALL: The circle whose equation is of the form $(x-h)^2 + (y-k)^2=r^2$ has its center at $(h, k)$ and has a radius of $r$ units. Thus, the given circle has: center at (1, 2) radius = $\sqrt9 = 3$
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