Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.9 - The Coordinate Plane; Graphs of Equations; Circles - 1.9 Exercises - Page 101: 4

Answer

"... $x$ by $\underline2$ and $y$ by $\underline3$." $(-2, \frac{1}{2})$ $(-1, 0)$ $(0, \frac{1}{2})$ $(1, 1)$ $(2, \frac{3}{2})$ See the image below.

Work Step by Step

The form of point coordinates is $(x, y)$, so $(2 ,3)$ means that $x=2$ and $y=3$ "... $x$ by $\underline2$ and $y$ by $\underline3$." $2y=x+1$ Simplify for easier calculation: $y=\frac{x+1}{2}$ $x=-2$ $y=\frac{-2+1}{2}=-\frac{1}{2}$ $(-2, \frac{1}{2})$ $x=-1$ $y=\frac{-1+1}{2}=\frac{0}{2}=0$ $(-1, 0)$ $x=0$ $y=\frac{0+1}{2}=\frac{1}{2}$ $(0, \frac{1}{2})$ $x=1$ $y=\frac{1+1}{2}=\frac{2}{2}=1$ $(1, 1)$ $x=2$ $y=\frac{2+1}{2}=\frac{3}{2}$ $(2, \frac{3}{2})$
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