Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.8 - Inequalities - 1.8 Exercises: 86

Answer

SOLUTION $x\leq-9$ and $x\geq7$ GRAPH In the real number line put and -9 with a close cirlce and draw a line towards $-\infty$. Then put a 7 with a close circle and draw a line pointin towards $\infty$.

Work Step by Step

$\mid\frac{x+1}{2}\mid \geq4$ So you divide it in two to take the absolute value away $\frac{x+1}{2} \leq-4$ Or $\frac{x+1}{2} \geq4$. First let’s solve one at a time $$\frac{x+1}{2} \leq-4$$ $$x+1\leq-8$$ $$x\leq-9$$ Now the second one $$\frac{x+1}{2} \geq4$$ $$x+1\geq8$$ $$x\geq7$$ So we have two solutions $x\leq-9$ and $x\geq7$ GRAPH In the real number line put and -9 with a close cirlce and draw a line towards $-\infty$. Then put a 7 with a close circle and draw a line pointin towards $\infty$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.