Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.8 - Inequalities - 1.8 Exercises - Page 89: 50

Answer

(-$\infty$,-3] $\cup$ [3,$\infty$)

Work Step by Step

$x^{2}$ $\geq$ 9 $x^{2}$-9 $\geq$ 0 (x+3)(x-3) $\geq$ 0 Factors are zero when x=3 or -3, endpoints satisfy the inequality , plug in numbers from intervals to decide which of them satisfy the inequality.
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