## Precalculus: Mathematics for Calculus, 7th Edition

$\frac{(y-2)}{(3-y)}$
Looking at the numerator: Combine $1-\frac{2}{y}$ by multiplying $1$ by $\frac{y}{y}$. This then becomes: $\frac{y-2}{y}$. Looking at the denominator: Combine $\frac{3}{y}-1$ by multiplying $1$ by $\frac{y}{y}$. This then becomes: $\frac{3-y}{y}$. The fraction is now: $=\frac{\frac{y-2}{y}}{\frac{3-y}{y}}$ Divide the fractions: $=\frac{(y-2)y}{y(3-y)}$ Cancel the common factor of $y$: $=\frac{(y-2)}{(3-y)}$