Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 23

Answer

$\frac{2x^{2}+3x}{2x-3}$

Work Step by Step

$\frac{2x^{3}-x^{2}-6x}{2x^{2}-7x+6}$ = $\frac{x(2x^{2}-x-6)}{2x^{2}-7x+6}$ = $\frac{x(2x+3)(x-2)}{(2x-3)(x-2)}$ = $\frac{x(2x+3)}{(2x-3)}$ = $\frac{2x^{2}+3x}{2x-3}$
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