Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 22

Answer

$\frac{y-6}{2y+1}$

Work Step by Step

factor both the numerator and denominator: from : $\frac{y^{2}-3y-18}{2y^{2}+7y+3}$ to: $\frac{(y-6)(y+3)}{(2y+1)(y+3)}$ then cancel like terms: (y+3): $\frac{(y-6)}{(2y+1)}$
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