## Precalculus: Mathematics for Calculus, 7th Edition

$\frac{y-6}{2y+1}$
factor both the numerator and denominator: from : $\frac{y^{2}-3y-18}{2y^{2}+7y+3}$ to: $\frac{(y-6)(y+3)}{(2y+1)(y+3)}$ then cancel like terms: (y+3): $\frac{(y-6)}{(2y+1)}$