Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 21

Answer

$\frac{y^{2}+y}{y^{2}-1}=\frac{y}{y-1}$

Work Step by Step

$\frac{y^{2}+y}{y^{2}-1}=\frac{y(y+1)}{(y+1)(y-1)}=\frac{y}{y-1}$
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