Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 16

Answer

$\frac{4(x^{2}-1)}{12(x+2)(x-1)}=\frac{(x+1)}{3(x+2)}$

Work Step by Step

$\frac{4(x^{2}-1)}{12(x+2)(x-1)}=\frac{4(x-1)(x+1)}{12(x+2)(x-1)}=\frac{(x+1)}{3(x+2)}$
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