## Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole

# Chapter 1 - Section 1.4 - Rational Expressions - 1.4 Exercises: 13

#### Answer

The domain is {$x|x\ne-1, x\ne2$}

#### Work Step by Step

Denominator cannot be $0$. Solve the denominator to find the value where $x=0$. Factor the polynomial in the denominator. $x^{2}-x-2=0$ $(x+1)(x-2)=0$ $x=-1$ and $x=2$

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