Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises: 44

Answer

$ x^3 - 9x^2 + 27x + 27$

Work Step by Step

$Multiply$ $the$ $algebraic$ $expressions$ $using$ $a$ $Special$ $Product$ $Formula$ $and$ $simplify:$ $(x-3)^3$ Use the Cube of a Difference Formula: $(A-B)^3 = A^3 - 3A^2B + 3AB^2 - B^3$ $(x-3)^3$ = $x^3$ - $(3\times x^2 \times 3)$ + $(3\times x \times 3^2)$ + $3^3$ $= x^3 - 9x^2 + 27x + 27$
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