Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises: 42

Answer

$ y - 2$

Work Step by Step

$Multiply$ $the$ $algebraic$ $expressions$ $using$ $a$ $Special$ $Product$ $Formula$ $and$ $simplify:$ $(\sqrt y + \sqrt 2)(\sqrt y - \sqrt 2)$ Use the Sum and Difference of Same Terms Product Formula: $(A+B)(A-B) = A^2-B^2$ $(\sqrt y + \sqrt 2)(\sqrt y - \sqrt 2) = (\sqrt y)^2 - (\sqrt 2)^2$ Note: $(\sqrt x)^2 = x^{\frac{1}{2}\times \frac{2}{1}} = x^1 = x$ $y^1 - 2^1$ $= y - 2$
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