Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 1 - Section 1.3 - Algebraic Expressions - 1.3 Exercises: 40

Answer

$4y^2 - 25$

Work Step by Step

$Multiply$ $the$ $algebraic$ $expressions$ $using$ $a$ $Special$ $Product$ $Formula$ $and$ $simplify:$ $(2y+5)(2y-5)$ Use the Sum and Difference of Same Terms Product Formula: $(A+B)(A-B) = A^2-B^2$ $(2y+5)(2y-5) = (2y)^2 - 5^2$ $= 4y^2 - 25$
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